2(1[x+3]1)-8x=36

Solution for 2(1[x+3]1)-8x=36 equation:

Simplifying
2(1[x + 3] * 1) + -8x = 36

Reorder the terms:
2(1[3 + x] * 1) + -8x = 36

Reorder the terms for easier multiplication:
2(1 * 1[3 + x]) + -8x = 36

Multiply 1 * 1
2(1[3 + x]) + -8x = 36
2([3 * 1 + x * 1]) + -8x = 36
2([3 + 1x]) + -8x = 36
(3 * 2 + 1x * 2) + -8x = 36
(6 + 2x) + -8x = 36

Combine like terms: 2x + -8x = -6x
6 + -6x = 36

Solving
6 + -6x = 36

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -6x = 36 + -6

Combine like terms: 6 + -6 = 0
0 + -6x = 36 + -6
-6x = 36 + -6

Combine like terms: 36 + -6 = 30
-6x = 30

Divide each side by '-6'.
x = -5

Simplifying
x = -5